# Project Euler question #6 solved in Java

### By Steve Claridge on 2014-03-15.

The sum of the squares of the first ten natural numbers is,

1^2^ + 2^2^ + ... + 10^2^ = 385 The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)^2^ = 55^2^ = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

My solution in Java:

```
public class Euler6
{
private long sumOfSquares()
{
long total = 0;
for ( int i = 1; i < 101; i++)
{
total += i*i;
} return total;
} private long squareOfSums()
{
long total = 0;
for ( int i = 1; i < 101; i++ )
{
total += i;
}
return total*total;
} public long answer()
{
return squareOfSums() - sumOfSquares();
}
}
```