Project Euler question #6 solved in Java

Project Euler question 6 is:

The sum of the squares of the first ten natural numbers is,
1^2^ + 2^2^ + ... + 10^2^ = 385 The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)^2^ = 55^2^ = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

My solution in Java:

public class Euler6
{
    private long sumOfSquares()
    {
        long total = 0;
        for ( int i = 1; i < 101; i++)
        {
            total += i*i;
        }         return total;
    }     private long squareOfSums()
    {
        long total = 0;
        for ( int i = 1; i < 101; i++ )
        {
            total += i;
        }
        return total*total;
    }     public long answer()
    {
        return squareOfSums() - sumOfSquares();
    }
}