The sum of the squares of the first ten natural numbers is,
12 + 22 + … + 102 = 385The square of the sum of the first ten natural numbers is,
(1 + 2 + … + 10)2 = 552 = 3025Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025
385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
My solution in Java:
public class Euler6 { private long sumOfSquares() { long total = 0; for ( int i = 1; i < 101; i++) { total += i*i; } return total; } private long squareOfSums() { long total = 0; for ( int i = 1; i < 101; i++ ) { total += i; } return total*total; } public long answer() { return squareOfSums() - sumOfSquares(); } }